0=300(28x^2-5)

Solution for 0=300(28x^2-5) equation:

0=300(28x^2-5)

We move all terms to the left:

0-(300(28x^2-5))=0

We add all the numbers together, and all the variables

-(300(28x^2-5))=0


We calculate terms in parentheses: -(300(28x^2-5)), so:

300(28x^2-5)

We multiply parentheses

8400x^2-1500

Back to the equation:

-(8400x^2-1500)


We get rid of parentheses

-8400x^2+1500=0

a = -8400; b = 0; c = +1500;
Δ = b2-4ac
Δ = 02-4·(-8400)·1500
Δ = 50400000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{50400000}=\sqrt{1440000*35}=\sqrt{1440000}*\sqrt{35}=1200\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1200\sqrt{35}}{2*-8400}=\frac{0-1200\sqrt{35}}{-16800}
=-\frac{1200\sqrt{35}}{-16800}
=-\frac{\sqrt{35}}{-14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1200\sqrt{35}}{2*-8400}=\frac{0+1200\sqrt{35}}{-16800}
=\frac{1200\sqrt{35}}{-16800}
=\frac{\sqrt{35}}{-14}
$